Two numbers are in ratio 6:12. Their difference is 91. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 6:12. Their difference is 91. What is their sum?

A. 198

B. 449

C. 533

D. 396

Answer: Option D

Solution (By JKSSB Mock Tests)

Numbers 6k, 12k. Difference |6-12|k = 91 ⇒ k = 15. Sum = (6+12)k ≈ 396.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Ratio of present ages of A and B is 7:8. After 11 years, the ratio becomes 10:10. Present age of A is?

A. 161 years

B. 156 years

C. 322 years

D. 166 years

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Correct Answer: Option A

Explanation:
Let ages 7k and 8k. Then (7k + 11)/(8k + 11) = 10/10. Solving gives k ≈ 23, age of A = 7*23 = 161.

This question belongs to: Maths Ratio and Proportion

Question #2

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Two numbers are in the ratio 12:5 and their sum is 771. Find the numbers.

A. 523 and 234

B. 556 and 206

C. 1080 and 450

D. 540 and 225

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Correct Answer: Option D

Explanation:
Numbers = 12k and 5k. 12k + 5k = 771 ⇒ k = 45. Thus, numbers are 540 and 225.

This question belongs to: Maths Ratio and Proportion

Question #3

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Ratio of present ages of A and B is 7:8. After 6 years, the ratio becomes 8:9. Present age of A is?

A. 105 years

B. 110 years

C. 97 years

D. 210 years

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Correct Answer: Option A

Explanation:
Let ages 7k and 8k. Then (7k + 6)/(8k + 6) = 8/9. Solving gives k ≈ 15, age of A = 7*15 = 105.

This question belongs to: Maths Ratio and Proportion

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