Two numbers are in ratio 6:12. Their difference is 91. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 6:12. Their difference is 91. What is their sum?

A. 533

B. 396

C. 449

D. 198

Answer: Option B

Solution (By JKSSB Mock Tests)

Numbers 6k, 12k. Difference |6-12|k = 91 ⇒ k = 15. Sum = (6+12)k ≈ 396.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1

Two numbers are in the ratio 12:6 and their sum is 224. Find the numbers.

A. 288 and 144

B. 156 and 45

C. 144 and 72

D. 132 and 88

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Correct Answer: Option C

Explanation:
Numbers = 12k and 6k. 12k + 6k = 224 ⇒ k = 12. Thus, numbers are 144 and 72.

This question belongs to: Maths Ratio and Proportion

Question #2

If a:b = 4:5 and b:c = 5:11, then a:b:c = ?

A. 4:6:11

B. 4:5:11

C. 8:10:22

D. 3:5:12

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Correct Answer: Option B

Explanation:
Combine ratios: a:b = 4:5, b:c = 5:11 ⇒ a:b:c = 4:5:11.

This question belongs to: Maths Ratio and Proportion

Question #3

Ratio of present ages of A and B is 5:6. After 9 years, the ratio becomes 7:7. Present age of A is?

A. 105 years

B. 200 years

C. 100 years

D. 95 years

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Correct Answer: Option C

Explanation:
Let ages 5k and 6k. Then (5k + 9)/(6k + 9) = 7/7. Solving gives k ≈ 20, age of A = 5*20 = 100.

This question belongs to: Maths Ratio and Proportion

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