Two numbers are in ratio 7:4. Their difference is 53. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 7:4. Their difference is 53. What is their sum?

A. 471

B. 209

C. 547

D. 418

Answer: Option D

Solution (By JKSSB Mock Tests)

Numbers 7k, 4k. Difference |7-4|k = 53 ⇒ k = 17. Sum = (7+4)k ≈ 418.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1

If a:b = 4:10 and b:c = 10:12, then a:b:c = ?

A. 3:10:13

B. 8:20:24

C. 4:11:12

D. 4:10:12

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Correct Answer: Option D

Explanation:
Combine ratios: a:b = 4:10, b:c = 10:12 ⇒ a:b:c = 4:10:12.

This question belongs to: Maths Ratio and Proportion

Question #2

Two numbers are in the ratio 13:5 and their sum is 464. Find the numbers.

A. 314 and 136

B. 341 and 114

C. 325 and 125

D. 650 and 250

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Correct Answer: Option C

Explanation:
Numbers = 13k and 5k. 13k + 5k = 464 ⇒ k = 25. Thus, numbers are 325 and 125.

This question belongs to: Maths Ratio and Proportion

Question #3

If a:b = 4:5 and b:c = 5:12, then a:b:c = ?

A. 3:5:13

B. 8:10:24

C. 4:6:12

D. 4:5:12

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Correct Answer: Option D

Explanation:
Combine ratios: a:b = 4:5, b:c = 5:12 ⇒ a:b:c = 4:5:12.

This question belongs to: Maths Ratio and Proportion

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