Two numbers are in ratio 7:4. Their difference is 53. What is their sum? MCQ with Answer and Explanation

Two numbers are in ratio 7:4. Their difference is 53. What is their sum?
A. 209
B. 547
C. 471
D. 418
Answer: Option D
Solution (By JKSSB Mock Tests)
Numbers 7k, 4k. Difference |7-4|k = 53 ⇒ k = 17. Sum = (7+4)k ≈ 418.

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Practice More Ratio and Proportion Questions

Question #1
Two numbers are in the ratio 13:4 and their sum is 771. Find the numbers.
A. 609 and 170
B. 585 and 180
C. 578 and 197
D. 1170 and 360

Correct Answer: Option B


Explanation:
Numbers = 13k and 4k. 13k + 4k = 771 ⇒ k = 45. Thus, numbers are 585 and 180.

This question belongs to: Maths Ratio and Proportion
Question #2
Milk and water are in ratio 9:3 in a 408 L mixture. Quantity of milk?
A. 306 L
B. 612 L
C. 349 L
D. 102 L

Correct Answer: Option A


Explanation:
Total parts = 12. Milk = [9 / (9+3)] × 408 = 306 L.

This question belongs to: Maths Ratio and Proportion
Question #3
If a:b = 5:6 and b:c = 6:11, then a:b:c = ?
A. 5:7:11
B. 5:6:11
C. 10:12:22
D. 4:6:12

Correct Answer: Option B


Explanation:
Combine ratios: a:b = 5:6, b:c = 6:11 ⇒ a:b:c = 5:6:11.

This question belongs to: Maths Ratio and Proportion