Two numbers are in ratio 7:4. Their difference is 73. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 7:4. Their difference is 73. What is their sum?

A. 594

B. 636

C. 734

D. 297

Answer: Option A

Solution (By JKSSB Mock Tests)

Numbers 7k, 4k. Difference |7-4|k = 73 ⇒ k = 24. Sum = (7+4)k ≈ 594.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1

If a:b = 3:5 and b:c = 5:6, then a:b:c = ?

A. 3:6:6

B. 6:10:12

C. 3:5:6

D. 2:5:7

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Correct Answer: Option C

Explanation:
Combine ratios: a:b = 3:5, b:c = 5:6 ⇒ a:b:c = 3:5:6.

This question belongs to: Maths Ratio and Proportion

Question #2

Ratio of present ages of A and B is 5:5. After 5 years, the ratio becomes 6:7. Present age of A is?

A. 90 years

B. 45 years

C. 50 years

D. 39 years

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Correct Answer: Option B

Explanation:
Let ages 5k and 5k. Then (5k + 5)/(5k + 5) = 6/7. Solving gives k ≈ 9, age of A = 5*9 = 45.

This question belongs to: Maths Ratio and Proportion

Question #3

Ratio of present ages of A and B is 5:4. After 12 years, the ratio becomes 8:5. Present age of A is?

A. 230 years

B. 120 years

C. 111 years

D. 115 years

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Correct Answer: Option D

Explanation:
Let ages 5k and 4k. Then (5k + 12)/(4k + 12) = 8/5. Solving gives k ≈ 23, age of A = 5*23 = 115.

This question belongs to: Maths Ratio and Proportion

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