Two numbers are in ratio 7:4. Their difference is 73. What is their sum? MCQ with Answer and Explanation

Two numbers are in ratio 7:4. Their difference is 73. What is their sum?
A. 734
B. 636
C. 594
D. 297
Answer: Option C
Solution (By JKSSB Mock Tests)
Numbers 7k, 4k. Difference |7-4|k = 73 ⇒ k = 24. Sum = (7+4)k ≈ 594.

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Practice More Ratio and Proportion Questions

Question #1
If a:b = 5:6 and b:c = 6:9, then a:b:c = ?
A. 5:7:9
B. 5:6:9
C. 10:12:18
D. 4:6:10

Correct Answer: Option B


Explanation:
Combine ratios: a:b = 5:6, b:c = 6:9 ⇒ a:b:c = 5:6:9.

This question belongs to: Maths Ratio and Proportion
Question #2
Two numbers are in ratio 7:12. Their difference is 101. What is their sum?
A. 334
B. 152
C. 423
D. 304

Correct Answer: Option D


Explanation:
Numbers 7k, 12k. Difference |7-12|k = 101 ⇒ k = 20. Sum = (7+12)k ≈ 304.

This question belongs to: Maths Ratio and Proportion
Question #3
Find the mean proportional between 11 and 38.
A. 49
B. 23
C. 40
D. 20

Correct Answer: Option D


Explanation:
Mean proportional = √(11 × 38) = √(418) = 20.

This question belongs to: Maths Ratio and Proportion