Two numbers are in ratio 9:11. Their difference is 102. What is their sum? MCQ with Answer and Explanation

Two numbers are in ratio 9:11. Their difference is 102. What is their sum?
A. 422
B. 400
C. 200
D. 482
Answer: Option B
Solution (By JKSSB Mock Tests)
Numbers 9k, 11k. Difference |9-11|k = 102 ⇒ k = 51. Sum = (9+11)k ≈ 400.

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Practice More Ratio and Proportion Questions

Question #1
Ratio of present ages of A and B is 3:8. After 10 years, the ratio becomes 4:10. Present age of A is?
A. 44 years
B. 102 years
C. 51 years
D. 56 years

Correct Answer: Option C


Explanation:
Let ages 3k and 8k. Then (3k + 10)/(8k + 10) = 4/10. Solving gives k ≈ 17, age of A = 3*17 = 51.

This question belongs to: Maths Ratio and Proportion
Question #2
If a:b = 8:3 and b:c = 3:8, then a:b:c = ?
A. 8:4:8
B. 8:3:8
C. 7:3:9
D. 16:6:16

Correct Answer: Option B


Explanation:
Combine ratios: a:b = 8:3, b:c = 3:8 ⇒ a:b:c = 8:3:8.

This question belongs to: Maths Ratio and Proportion
Question #3
If a:b = 2:4 and b:c = 4:9, then a:b:c = ?
A. 2:4:9
B. 1:4:10
C. 4:8:18
D. 2:5:9

Correct Answer: Option A


Explanation:
Combine ratios: a:b = 2:4, b:c = 4:9 ⇒ a:b:c = 2:4:9.

This question belongs to: Maths Ratio and Proportion