Two numbers are in the ratio 13:11 and their sum is 287. Find the numbers. MCQ with Answer and Explanation

Two numbers are in the ratio 13:11 and their sum is 287. Find the numbers.
A. 143 and 121
B. 138 and 127
C. 158 and 106
D. 286 and 242
Answer: Option A
Solution (By JKSSB Mock Tests)
Numbers = 13k and 11k. 13k + 11k = 287 ⇒ k = 11. Thus, numbers are 143 and 121.

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Practice More Ratio and Proportion Questions

Question #1
Two numbers are in ratio 7:12. Their difference is 133. What is their sum?
A. 434
B. 399
C. 507
D. 199

Correct Answer: Option B


Explanation:
Numbers 7k, 12k. Difference |7-12|k = 133 ⇒ k = 26. Sum = (7+12)k ≈ 399.

This question belongs to: Maths Ratio and Proportion
Question #2
Find the mean proportional between 11 and 45.
A. 44
B. 25
C. 56
D. 22

Correct Answer: Option D


Explanation:
Mean proportional = √(11 × 45) = √(495) = 22.

This question belongs to: Maths Ratio and Proportion
Question #3
Two numbers are in the ratio 12:9 and their sum is 569. Find the numbers.
A. 317 and 258
B. 324 and 243
C. 341 and 215
D. 648 and 486

Correct Answer: Option B


Explanation:
Numbers = 12k and 9k. 12k + 9k = 569 ⇒ k = 27. Thus, numbers are 324 and 243.

This question belongs to: Maths Ratio and Proportion