Walking at 5/6 of his baseline typical speed, a courier agent reaches his office terminal 15 minutes late. Find his typical baseline time parameter. MCQ with Answer and Explanation

Walking at 5/6 of his baseline typical speed, a courier agent reaches his office terminal 15 minutes late. Find his typical baseline time parameter.
A. 70 minutes
B. 80 minutes
C. 75 minutes
D. 85 minutes
Answer: Option C
Solution (By JKSSB Mock Tests)
New speed = 5/6 of usual speed => New time = 6/5 of usual time. Difference = 1/5 of usual time = 15 minutes. Typical baseline time parameter = 15 * 5 = 75 minutes.

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Practice More Time Speed and Distance Questions

Question #1
A vehicle covers a path of 360 km at a certain speed. If the speed is increased by 10 km/h, the trip takes exactly 3 hours less. Find the original speed of the vehicle.
A. 30 km/h
B. 35 km/h
C. 40 km/h
D. 25 km/h

Correct Answer: Option A


Explanation:
Let original speed be s. 360/s - 360/(s+10) = 3 => 120/s - 120/(s+10) = 1 => 120(10) = s(s+10) => 1200 = s(s+10). Solving s^2 + 10s - 1200 = 0 gives (s - 30)(s + 40) = 0. Since speed is positive, s = 30 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A wheel makes 2000 revolutions to cover a distance of 1760 meters. Find the radius of the wheel.
A. 18 cm
B. 12 cm
C. 16 cm
D. 14 cm

Correct Answer: Option D


Explanation:
Distance covered in 1 revolution = 1760 / 2000 = 0.88 meters = 88 cm. Circumference = 2 * (22/7) * r = 88 cm => (44/7) * r = 88 => r = 14 cm.

This question belongs to: Maths Time Speed and Distance
Question #3
A person can row 6 km/h in still water. If the speed of the stream is 2 km/h, how much time will he take to row a distance of 16 km downstream?
A. 4 hours
B. 3 hours
C. 2 hours
D. 5 hours

Correct Answer: Option C


Explanation:
Downstream speed = 6 + 2 = 8 km/h. Time = Distance / Speed = 16 / 8 = 2 hours.

This question belongs to: Maths Time Speed and Distance