A locomotive express train passes a milestone column track point in 15 seconds flat. If the speed index of the train records at 72 km/h, find the length of the train layout. MCQ with Answer and Explanation
A locomotive express train passes a milestone column track point in 15 seconds flat. If the speed index of the train records at 72 km/h, find the length of the train layout.
A. 320 meters
B. 300 meters
C. 350 meters
D. 280 meters
Answer: Option B
Solution (By JKSSB Mock Tests)
Speed of train = 72 * (5/18) = 20 m/s. Length of train layout = Speed * Time = 20 * 15 = 300 meters.
Explanation:
Let total distance be 100 km. First part: 40 km at 40 km/h => time = 1 hour. Remaining distance = 60 km. Second part: 50% of 60 = 30 km at 30 km/h => time = 1 hour. Remaining distance = 30 km. Third part: 30 km at 15 km/h => time = 2 hours. Total time = 1 + 1 + 2 = 4 hours. Average speed = 100 / 4 = 25 km/h.
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