What does the acronym PROM stand for? MCQ with Answer and Explanation

What does the acronym PROM stand for?
A. Primary Read-Only Memory
B. Programmable Read-Only Memory
C. Parallel Read-Only Memory
D. Permanent Read-Only Memory
Answer: Option B
Solution (By JKSSB Mock Tests)
PROM stands for Programmable Read-Only Memory, which can be programmed once after manufacturing using a special device.

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Practice More Memory and Storage Devices Questions

Question #1
What is the function of a memory overclocking?
A. To increase memory capacity
B. To improve error correction
C. To reduce voltage
D. To run memory at higher speeds than rated

Correct Answer: Option D


Explanation:
Overclocking memory involves running it at a higher clock speed than its default, to gain performance, but may require higher voltage and cooling.

This question belongs to: Computer Memory and Storage Devices
Question #2
Which of the following is an advantage of optical storage over magnetic storage?
A. Higher capacity
B. Faster read/write speeds
C. Lower cost per GB
D. More durable (resistant to magnetic fields)

Correct Answer: Option D


Explanation:
Optical discs are immune to magnetic fields and are relatively durable under normal handling, while magnetic disks can be damaged by strong magnetic fields. However, optical is slower and lower capacity.

This question belongs to: Computer Memory and Storage Devices
Question #3
Which of the following describes the operational concept of a 'Virtual Memory'?
A. A cloud-based storage system that bypasses the local operating system.
B. A dedicated memory chip installed exclusively inside advanced graphics cards.
C. An extremely large main memory array made of high-speed SRAM.
D. An illusion of an extremely large main memory achieved by using a part of secondary storage.

Correct Answer: Option D


Explanation:
Virtual memory is a memory management technique that uses secondary storage (like an HDD or SSD) to simulate additional RAM, allowing programs to run even if they exceed physical memory capacity.

This question belongs to: Computer Memory and Storage Devices