A 50 kg man climbs 30 steps each 20 cm high in 10 s. His power (g=10 m/s²) is
A. 150 W
B. 600 W
C. 300 W
D. 30 W
Answer: Option C
Solution (By JKSSB Mock Tests)
Total height = 30 × 0.2 m = 6 m. Work done = mgh = 50 × 10 × 6 = 3000 J. Power = Work/time = 3000/10 = 300 W. If steps height and number given, calculate total vertical displacement. Time taken for climbing is important. Power is rate of doing work.
Explanation:
Frequency determines pitch: higher frequency ⇒ higher pitch (e.g., whistle vs drum). Loudness depends on amplitude; quality (timbre) on waveform/harmonics; speed on medium properties (density, elasticity). This is a fundamental characteristic of sound perception. Memory aid: 'Frequency → Pitch; Amplitude → Loudness'. Competitive exams often test these distinctions to identify misconceptions. Note: Speed of sound is independent of frequency in a given medium (non-dispersive for audible sound in air). Always link physical quantities to perceptual attributes correctly.
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