The force of attraction between two bodies of masses 1 kg each separated by 1 m is (G=6.67×10⁻¹¹) MCQ with Answer and Explanation

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The force of attraction between two bodies of masses 1 kg each separated by 1 m is (G=6.67×10⁻¹¹)

A. 6.67 × 10⁻⁷ N

B. 6.67 × 10⁻⁵ N

C. 6.67 × 10⁻¹¹ N

D. 6.67 × 10⁻⁹ N

Answer: Option C

Solution (By JKSSB Mock Tests)

F = G×1×1/1² = 6.67×10⁻¹¹ N.

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Question #1

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A stone is thrown vertically upward with velocity 49 m/s. The time after which it returns to thrower is (g=9.8)

A. 5 s

B. 10 s

C. 2.5 s

D. 15 s

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Correct Answer: Option B

Explanation:
Time of flight T = 2u/g = 2×49/9.8 = 98/9.8 = 10 s. Up and down symmetric. Max height = u²/(2g) = 122.5 m.

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Question #2

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The essential difference between AC and DC is

A. Resistance

B. Voltage level

C. Magnitude only

D. Direction of current

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Correct Answer: Option D

Explanation:
AC changes direction periodically, DC unidirectional.

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Question #3

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A person weighs 60 kg on Earth. His weight on moon will be (g_moon = g/6)

A. 360 kg

B. 6 kg

C. 10 kg

D. 60 kg

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Correct Answer: Option C

Explanation:
Weight = mg. On moon, weight = 60×(g/6)/g = 10 kg wt. Mass remains 60 kg, but weight is 10 kg force.

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