The percentage error in measurement of a cube's side is 2%. Maximum percentage error in its volume is:
A. 8%
B. 6%
C. 2%
D. 4%
Answer: Option B
Solution (By JKSSB Mock Tests)
Volume V = a³. For error propagation: % error in V = 3 × % error in a. Given 2% error in side, volume error = 3×2% = 6%. Power rule: if Q = xⁿ, %ΔQ = |n|×%Δx. Memory tip: Volume depends on cube of length ⇒ errors triple. Common in experimental error analysis questions.
Explanation:
Kinetic energy K = p²/(2m) = (10)²/(2×2) = 100/4 = 25 J. Also, velocity v = p/m = 5 m/s, K = ½×2×5² = 25 J. Formula p²/(2m) is useful for quick computation. Always ensure units: kg, m/s, J.
Explanation:
I_rms defined so I_rms²R = average power, same heating as DC current. For sine wave: I_rms = I₀/√2. Memory tip: 'RMS: heating equivalence; use RMS for power calculations'. AC fundamentals frequently tested in competitive exams.
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