A body is thrown vertically upwards. At the highest point of its trajectory: MCQ with Answer and Explanation

A body is thrown vertically upwards. At the highest point of its trajectory:
A. Velocity and acceleration are zero
B. Velocity is maximum and acceleration is zero
C. Both velocity and acceleration are maximum
D. Velocity is zero but acceleration is g downward
Answer: Option D
Solution (By JKSSB Mock Tests)
At maximum height, vertical velocity becomes zero momentarily. However, acceleration due to gravity (g) acts downward throughout the motion, including at the peak. Thus acceleration is g ≈ 9.8 m/s² downward, not zero. Memory tip: 'Peak of projectile: v=0, a=g downward'. This conceptual question tests understanding of motion under gravity, frequently appearing in competitive exams. Always distinguish velocity (which changes) from acceleration (constant in free fall near Earth). Misconception that acceleration is zero at peak is a common trap.

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1 light year is equal to
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B. 9.46 × 10¹² km
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D. 3 × 10⁸ m

Correct Answer: Option B


Explanation:
Distance light travels in one year ≈ 9.46×10¹² km.

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Correct Answer: Option A


Explanation:
J.J. Thomson measured e/m using cathode ray deflection (1897). Millikan later measured e (oil drop). Memory aid: 'Thomson = e/m; Millikan = e'. Experimental physics history frequently tested in competitive exams.

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Question #3
A body is thrown vertically upward. At the highest point, its acceleration is
A. g upward
B. Variable
C. Zero
D. g downward

Correct Answer: Option D


Explanation:
At highest point velocity is zero, but acceleration due to gravity is still g (9.8 m/s²) downward. This causes it to fall back. Acceleration constant throughout free fall.

This question belongs to: Science Physics