A body moves with uniform acceleration. The graph between velocity and time is: MCQ with Answer and Explanation

A body moves with uniform acceleration. The graph between velocity and time is:
A. Parabola
B. Hyperbola
C. Straight line parallel to time axis
D. Straight line with positive slope
Answer: Option D
Solution (By JKSSB Mock Tests)
Uniform acceleration means constant rate of change of velocity: a = dv/dt = constant. Thus v = u + at, a linear equation in t. Graph is straight line with slope = acceleration. Parallel to time axis (A) implies zero acceleration (constant velocity). Parabola (C) is for position-time under constant acceleration. Memory tip: 'v-t graph slope = acceleration; area = displacement'. This graph interpretation question tests kinematics fundamentals, frequently examined in competitive exams. Always link graph features to physical quantities: slope, area, intercepts have specific meanings in motion graphs.

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Which SI prefix represents 10⁻⁶?
A. micro
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Correct Answer: Option A


Explanation:
Micro (μ) denotes 10⁻⁶ in SI system. Nano = 10⁻⁹, pico = 10⁻¹², milli = 10⁻³. Standard prefixes: kilo(10³), milli(10⁻³), micro(10⁻⁶), nano(10⁻⁹). Memory aid: 'Micro = millionth; μm = micrometer = 10⁻⁶ m'. Frequently tested for unit conversion proficiency in competitive exams.

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Question #2
The rate of change of displacement is
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Correct Answer: Option A


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Question #3
A 50 kg person climbs 30 steps each 15 cm high in 10 s. Power (g=10) is
A. 2250 W
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Correct Answer: Option D


Explanation:
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