A boy throws a ball vertically upward with velocity 20 m/s. Time after which ball returns to his hands (g=10) is MCQ with Answer and Explanation

A boy throws a ball vertically upward with velocity 20 m/s. Time after which ball returns to his hands (g=10) is
A. 8 s
B. 4 s
C. 2 s
D. 1 s
Answer: Option B
Solution (By JKSSB Mock Tests)
Total time = 2u/g = 40/10 = 4 s.

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Practice More Physics Questions

Question #1
Which of the following is a semiconductor?
A. Silver
B. Iron
C. Copper
D. Silicon

Correct Answer: Option D


Explanation:
Silicon and germanium are semiconductors.

This question belongs to: Science Physics
Question #2
A body is thrown vertically upward with speed 40 m/s. Distance travelled in last second of ascent (g=10)
A. 5 m
B. 20 m
C. 15 m
D. 35 m

Correct Answer: Option A


Explanation:
Time of ascent = u/g = 4 s. Distance in last second (4th) = ½g(1)²? Actually, during last second of upward journey, velocity becomes zero. Distance = ½g(1)² = 5 m. Formula: s = u - g/2 (2n-1) with n=4? Let's compute: s_nth = u - (g/2)(2n-1). For n=4 (4th second), s = 40 - 5×7 = 40 - 35 = 5 m. Yes.

This question belongs to: Science Physics
Question #3
The least count of a standard vernier calliper is generally
A. 0.001 cm
B. 1 cm
C. 0.1 cm
D. 0.01 cm

Correct Answer: Option D


Explanation:
Least count = 1 MSD - 1 VSD = 0.1 - 0.09 = 0.01 cm (common).

This question belongs to: Science Physics