A electric iron of 500 W is used for 2 hours. Energy consumed in kWh is MCQ with Answer and Explanation

A electric iron of 500 W is used for 2 hours. Energy consumed in kWh is
A. 0.5 kWh
B. 250 kWh
C. 1000 kWh
D. 1 kWh
Answer: Option D
Solution (By JKSSB Mock Tests)
0.5 kW × 2 h = 1 kWh.

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Practice More Physics Questions

Question #1
The device used to measure the speed of a vehicle is
A. Barometer
B. Odometer
C. Anemometer
D. Speedometer

Correct Answer: Option D


Explanation:
Speedometer measures instantaneous speed of vehicle. Odometer measures distance travelled. Anemometer wind speed. Barometer pressure.

This question belongs to: Science Physics
Question #2
The half-life of a radioactive substance is 10 days. After 30 days, the fraction remaining undecayed is:
A. 1/3
B. 1/8
C. 1/16
D. 1/2

Correct Answer: Option B


Explanation:
Number of half-lives n = total time / half-life = 30 days / 10 days = 3. Fraction remaining = (1/2)ⁿ = (1/2)³ = 1/8. This exponential decay law is fundamental in radioactivity. Memory tip: 'After n half-lives, fraction = 1/2ⁿ'. Competitive exams frequently test such calculations with varying time intervals. Always compute number of half-lives first. Note: Activity (decays per second) also reduces by same fraction. This problem assesses understanding of half-life concept beyond rote memorization.

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Question #3
Beta rays emitted by radioactive substances are essentially:
A. Neutrons
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C. Electromagnetic waves
D. High-speed electrons

Correct Answer: Option D


Explanation:
During beta decay, a neutron in an unstable nucleus transforms into a proton and an electron. The proton remains in the nucleus, but the electron is ejected at high speed. These ejected, high-energy electrons are called beta rays (or beta particles). Gamma rays are electromagnetic waves, and alpha particles are helium nuclei.

This question belongs to: Science Physics