A flywheel rotates at 120 rpm. Angular velocity in rad/s is MCQ with Answer and Explanation

A flywheel rotates at 120 rpm. Angular velocity in rad/s is
A. 6π
B. 4π
C. π
D. 2π
Answer: Option B
Solution (By JKSSB Mock Tests)
ω = 2π × (rpm/60) = 2π × 120/60 = 4π rad/s.

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Practice More Physics Questions

Question #1
The magnetic field inside a long straight solenoid carrying current is:
A. Non-uniform and circular
B. Uniform and parallel to axis
C. Zero
D. Radially outward

Correct Answer: Option B


Explanation:
Inside a long solenoid, magnetic field is uniform (constant magnitude and direction), parallel to the axis, given by B = μ₀nI, where n is turns per unit length. Outside, field is nearly zero. This uniformity makes solenoids useful for creating controlled magnetic fields. Memory tip: 'Solenoid: uniform B inside like bar magnet'. This conceptual question tests knowledge of magnetic field configurations, crucial for electromagnetism in competitive exams. Always distinguish solenoid field (uniform inside) from straight wire field (circular, non-uniform).

This question belongs to: Science Physics
Question #2
An object is placed between pole and focus of a concave mirror. The image is
A. Virtual, inverted, diminished
B. Real, inverted, enlarged
C. Virtual, erect, enlarged
D. Real, erect, enlarged

Correct Answer: Option C


Explanation:
Object between P and F of concave mirror gives virtual, erect, magnified image behind mirror. Used in shaving mirror, dentist mirror. Ray diagram shows diverging rays appearing to come from behind.

This question belongs to: Science Physics
Question #3
If the length of a wire is stretched to double its original length while keeping its volume constant, its new resistance will be:
A. Twice the original
B. Half the original
C. Four times the original
D. Unchanged

Correct Answer: Option C


Explanation:
Resistance R = rhoL/A. If the wire is stretched so length becomes L' = 2L, the volume (V = AL) must remain constant. Therefore, the new area A' must be A/2 to maintain V. The new resistance R' = rho(2L)/(A/2) = 4 * (rhoL/A) = 4R. Stretching a wire to double its length increases its resistance strictly by a factor of 4. This is a classic trap question compared to merely 'changing the wire'.

This question belongs to: Science Physics