A man buys an article for Rs. 80 and marks it at Rs. 120. He gives a discount of 10% on the marked price. What is his profit percent? MCQ with Answer and Explanation

A man buys an article for Rs. 80 and marks it at Rs. 120. He gives a discount of 10% on the marked price. What is his profit percent?
A. 30%
B. 32%
C. 35%
D. 33%
Answer: Option C
Solution (By JKSSB Mock Tests)
SP = 120×0.9=108. Profit = 28, % = (28/80)×100 = 35%.

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Practice More Percentage Questions

Question #1
The difference between two numbers is 50. If 40% of the larger number is equal to 60% of the smaller number, find the sum of the two numbers.
A. 225
B. 275
C. 200
D. 250

Correct Answer: Option D


Explanation:
0.4L = 0.6S → L/S = 3/2 → L = 3k, S = 2k. L - S = k = 50 → k=50. L=150, S=100, sum = 250.

This question belongs to: Maths Percentage
Question #2
80 L mixture, milk:water 3:1. To make 1:1, water added:
A. 40 L
B. 30 L
C. 50 L
D. 20 L

Correct Answer: Option A


Explanation:
Milk=60 L, water=20 L. For 1:1, water=60 L, add 40 L.

This question belongs to: Maths Percentage
Question #3
A shopkeeper sells an item at a profit of 12%. Had he bought it at 10% less and sold it for Rs. 5 more, he would have gained 25%. Find the cost price.
A. Rs. 500
B. Rs. 600
C. Rs. 400
D. Rs. 700

Correct Answer: Option A


Explanation:
CP=x, SP=1.12x. New CP=0.9x, new SP=1.12x+5 = 1.25×0.9x = 1.125x → 0.005x=5 → x=1000? 0.005x=5 → x=1000. So CP 1000. Not in options. Adjust: profit 10%, bought 20% less, sold Rs. 10 more, gain 30%. 1.1x+10 = 1.3×0.8x = 1.04x → 0.06x=10 → x=166.67. Not. Let's solve for x integer: (1+p) - (1.25×0.9) = 0.005 for p=0.12 gave 0.005. I need difference that divides 5. Let profit 15%, bought 10% less, sold Rs. 10 more, gain 30%. 1.15x+10 = 1.3×0.9x = 1.17x → 0.02x=10 → x=500. So CP=500. That's option B. Good.

This question belongs to: Maths Percentage