A number is divided into two parts. 40% of the first part exceeds 30% of the second part by 20, and 50% of the second part exceeds 25% of the first part by 25. Find the number. MCQ with Answer and Explanation

A number is divided into two parts. 40% of the first part exceeds 30% of the second part by 20, and 50% of the second part exceeds 25% of the first part by 25. Find the number.
A. 260
B. 300
C. 200
D. 240
Answer: Option A
Solution (By JKSSB Mock Tests)
Let parts x, y. 0.4x - 0.3y = 20 → 4x - 3y = 200. 0.5y - 0.25x = 25 → 20y - 10x = 1000 → 2y - x = 100. Solve: x = 2y - 100. Substitute: 4(2y-100)-3y=200 → 8y-400-3y=200 → 5y=600 → y=120, x=140, sum=260.

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Practice More Percentage Questions

Question #1
Batsman scored 110 runs with 3 fours, 8 sixes. % runs from running:
A. 42.5%
B. 40%
C. 50%
D. 45.45%

Correct Answer: Option D


Explanation:
Boundary runs = 12+48=60, running=50. % = (50/110)×100 ≈ 45.45%.

This question belongs to: Maths Percentage
Question #2
Population 2,00,000. First year +8%, second year -5%. Population after 2 years:
A. 2,05,200
B. 2,06,400
C. 2,07,600
D. 2,08,800

Correct Answer: Option A


Explanation:
2,00,000 × 1.08 × 0.95 = 2,05,200.

This question belongs to: Maths Percentage
Question #3
In an exam, 70% passed English, 65% Maths, 27% failed both, 248 passed both. Total students:
A. 360
B. 400
C. 420
D. 380

Correct Answer: Option B


Explanation:
Failed English=30%, Failed Maths=35%. Failed both=27%. Passed both = 100 - (30+35-27) = 62%. 62% = 248 → total = 400.

This question belongs to: Maths Percentage