A particle moves with velocity v = 3t² + 2t. Its acceleration at t = 2 s is:
A. 16 m/s²
B. 14 m/s²
C. 10 m/s²
D. 8 m/s²
Answer: Option B
Solution (By JKSSB Mock Tests)
Acceleration a = dv/dt = d(3t² + 2t)/dt = 6t + 2. At t = 2 s: a = 6(2) + 2 = 14 m/s². Differentiation of velocity gives instantaneous acceleration. Memory tip: a = dv/dt; for polynomial v(t), differentiate term by term. Tests calculus application in kinematics, common in advanced competitive exam questions.
Explanation:
Speed has magnitude only, scalar. Velocity is vector (speed + direction). Momentum and force are vectors. Distance is scalar, displacement vector.
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