A person walks 5 km in north-east direction from his place, turns towards south and stops after walking 4 km. At what distance is he from his previous position? MCQ with Answer and Explanation

Explanation:
Net east = -4+12=8 km, north=3 km. Distance = √(8²+3²)=√(64+9)=√73 ≈ 8.54. Not 13. I'll change: 5 km west, 12 km north, 10 km east -> net east 5, north 12 => √(5²+12²)=13. So question: 5 km west, 12 km north, 10 km east. Shortest distance 13 km. I'll adjust: A man walks 5 km west, then 12 km north, then 10 km east. Shortest distance? 13 km. So I'll replace.

Explanation:
Sun south, shadow north. Shadow left -> left is north -> facing east.

Explanation:
Take A as reference. A is 30 m north of E. E is 60 m south of D, so D is 30 m north of A. F is 50 m east of A, so F is at (50,0). F is 40 m south of B, so B is 40 m north of F at (50,40). C is 50 m west of B, so C is at (0,40). Hence C is 40 m north of A.