A person with myopia uses spectacles of power -2 D. Far point without glasses is MCQ with Answer and Explanation

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A person with myopia uses spectacles of power -2 D. Far point without glasses is

A. 50 cm

B. 2 m

C. 25 cm

D. Infinity

Answer: Option A

Solution (By JKSSB Mock Tests)

For myopia, corrective lens forms image of distant object at far point. 1/f = 1/(-far point) - 1/(-∞) => -2 = -1/F => F = 0.5 m = 50 cm.

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Question #1

A body executing SHM has amplitude 5 cm and time period 2 s. Maximum velocity is

A. 20π cm/s

B. 5π cm/s

C. 10π cm/s

D. 2.5π cm/s

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Correct Answer: Option B

Explanation:
v_max = ωA = (2π/T) A = (2π/2)×5 = 5π cm/s.

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Question #2

Refractive index n = c/v. For glass n=1.5, light speed is:

A. 1.5×10⁸ m/s

B. 2×10⁸ m/s

C. 4.5×10⁸ m/s

D. 3×10⁸ m/s

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Correct Answer: Option B

Explanation:
v = c/n = 3×10⁸/1.5 = 2×10⁸ m/s. Direct refractive index formula application. Memory tip: 'Higher n ⇒ slower light; v = c/n'. Basic optics calculation frequently tested in competitive exams to verify formula recall and unit handling.

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Question #3

A transformer steps up 220 V to 2200 V. The turn ratio (secondary to primary) is

A. 1:10

B. 220:1

C. 1:1

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Correct Answer: Option D

Explanation:
For ideal transformer, V_s/V_p = N_s/N_p. So N_s/N_p = 2200/220 = 10. So secondary turns 10 times primary. Ratio 10:1. Step-up increases voltage.

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