A population increases by 20% in the first year and decreases by 20% in the second year. What is the net change over the two years? MCQ with Answer and Explanation

Question

A population increases by 20% in the first year and decreases by 20% in the second year. What is the net change over the two years?

A. 4% decrease

B. 4% increase

C. 2% decrease

D. No change

Answer: Option A

Solution (By JKSSB Mock Tests)

Net change = (20)^2 / 100 = 4% decrease.

This question belongs to: Maths Percentage

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Question #1

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40% of a number is 60. 80% of that number is:

A. 100

B. 130

C. 120

D. 110

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Correct Answer: Option C

Explanation:
Number = 60/0.4 = 150, 80% of 150 = 120.

This question belongs to: Maths Percentage

Question #2

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A number is decreased by 10% and then increased by 20%. The net change is:

A. 8% increase

B. 12% increase

C. 6% increase

D. 10% increase

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Correct Answer: Option A

Explanation:
0.9 × 1.2 = 1.08, 8% increase.

This question belongs to: Maths Percentage

Question #3

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If the numerator of a fraction is increased by 20% and its denominator is decreased by 10%, the fraction becomes 3/5. Find the original fraction.

A. 2/5

B. 9/20

C. 7/15

D. 4/7

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Correct Answer: Option B

Explanation:
Let original = N/D. (1.2N)/(0.9D) = (4/3)(N/D) = 3/5 → N/D = (3/5)×(3/4) = 9/20.

This question belongs to: Maths Percentage

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