A pump lifts 100 kg of water through 5 m in 2 s. Power (g=10) is MCQ with Answer and Explanation

Question

Share Report Error

A pump lifts 100 kg of water through 5 m in 2 s. Power (g=10) is

A. 1000 W

B. 250 W

C. 500 W

D. 2500 W

Answer: Option D

Solution (By JKSSB Mock Tests)

Work = 100×10×5=5000 J. Power = 5000/2 = 2500 W.

This question belongs to: Science Physics

Request complete Subject PDF

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1

Three 3Ω resistors in parallel: equivalent resistance is:

A. 0.33Ω

B. 9Ω

C. 1Ω

D. 3Ω

View Answer & Solution Discuss

Get Complete Subject PDF for Science

Correct Answer: Option C

Explanation:
1/R_eq = 1/3 + 1/3 + 1/3 = 1 ⇒ R_eq = 1Ω. For n equal resistors in parallel: R_eq = R/n. Memory tip: 'Parallel: reciprocal sum; result < smallest resistor'. Basic circuit calculation frequently tested in competitive exams to verify parallel combination formula.

This question belongs to: Science Physics

Question #2

A man of mass 60 kg stands on a weighing machine in a lift accelerating upward at 2 m/s². Reading in kg wt (g=10) is

A. 72 kg

B. 60 kg

C. 80 kg

D. 48 kg

View Answer & Solution Discuss

Get Complete Subject PDF for Science

Correct Answer: Option A

Explanation:
Apparent weight = m(g+a) = 60×12 = 720 N. In kg wt, 720/10 = 72 kg. So machine shows 72 kg. Downward acceleration would show less.

This question belongs to: Science Physics

Question #3

Momentum is conserved in

A. Only elastic collisions

B. Only inelastic collisions

C. All collisions

D. No collisions

View Answer & Solution Discuss

Get Complete Subject PDF for Science

Correct Answer: Option C

Explanation:
Momentum conserved in all collisions if no external force. KE conserved only in elastic.

This question belongs to: Science Physics

Explore All Physics MCQs