A spring of spring constant k is stretched by x. The potential energy stored is MCQ with Answer and Explanation

A spring of spring constant k is stretched by x. The potential energy stored is
A. ½kx
B. kx
C. kx²
D. ½kx²
Answer: Option D
Solution (By JKSSB Mock Tests)
Elastic potential energy stored in a stretched/compressed spring is ½kx², where x is displacement from equilibrium. This is work done against spring force which is average force times displacement. Work = ½Fx = ½(kx)x = ½kx². Similar to capacitor energy ½CV².

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