A student needs 30% to pass. He scores 40 marks and fails by 20 marks. What is the total marks? MCQ with Answer and Explanation

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A student needs 30% to pass. He scores 40 marks and fails by 20 marks. What is the total marks?

A. 150

B. 300

C. 250

D. 200

Answer: Option D

Solution (By JKSSB Mock Tests)

Passing marks = 40 + 20 = 60. 30% of Maximum = 60. Maximum = 60 * (100 / 30) = 200.

This question belongs to: Maths Percentage

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Question #1

Price up 20%, person buys 2 kg less for Rs. 60. Original price/kg:

A. Rs. 5

B. Rs. 7

C. Rs. 4

D. Rs. 6

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Correct Answer: Option A

Explanation:
Original price x, xy=60. New 1.2x(y-2)=60 → 1.2×60 - 2.4x =60 → x=5.

This question belongs to: Maths Percentage

Question #2

A trader bought articles for Rs. 1500. Five were damaged, rest sold at Rs. 3 more than CP each, total profit Rs. 75. Number of articles:

A. 70

B. 80

C. 75

D. 60

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Correct Answer: Option C

Explanation:
Let n articles, CP each=1500/n. Sold (n-5) at (1500/n +3). SP = (n-5)(1500/n +3)=1575. Solving gives n=75.

This question belongs to: Maths Percentage

Question #3

If A is 20% less than B, then B is what percentage more than A?

A. 30%

B. 20%

C. 15%

D. 25%

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Correct Answer: Option D

Explanation:
Formula: (R / (100 - R)) * 100. Here R = 20. (20 / 80) * 100 = (1 / 4) * 100 = 25%.

This question belongs to: Maths Percentage

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