A sum of money placed at compound interest becomes double of itself in 8 years. In how many years will it become 16 times of itself? MCQ with Answer and Explanation

A sum of money placed at compound interest becomes double of itself in 8 years. In how many years will it become 16 times of itself?
A. 48 years
B. 24 years
C. 32 years
D. 40 years
Answer: Option C
Solution (By JKSSB Mock Tests)
The sum becomes 2^1 times in 8 years. It will become 16 (2^4) times in 4 * 8 = 32 years.

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Practice More Compound Interest Questions

Question #1
The compound interest on a sum for 2 years at 10% compounded half-yearly is Rs. 4310.12. The sum is:
A. Rs. 19000
B. Rs. 18000
C. Rs. 20000
D. Rs. 21000

Correct Answer: Option C


Explanation:
CI = P[(1.05)⁴ − 1] = P × 0.21550625 = 4310.125 ⇒ P = 4310.125 / 0.21550625 = 20000.

This question belongs to: Maths Compound Interest
Question #2
At what rate percent per annum will Rs. 8000 amount to Rs. 9261 in 3 years, compound interest compounded annually?
A. 4%
B. 6%
C. 8%
D. 5%

Correct Answer: Option D


Explanation:
Amount/Principal = 9261 / 8000 = (21 / 20)^3. Therefore, 1 + R/100 = 21/20 => R/100 = 1/20 => R = 5%.

This question belongs to: Maths Compound Interest
Question #3
If a sum of Rs. 8000 becomes Rs. 9261 in 3 years at compound interest compounded annually, find the rate of interest per annum.
A. 6%
B. 5%
C. 8%
D. 4%

Correct Answer: Option B


Explanation:
Amount/Principal = 9261 / 8000 = (21 / 20)^3. Therefore, (1 + R/100)^3 = (21/20)^3 => 1 + R/100 = 21/20 => R/100 = 1/20 => R = 5%.

This question belongs to: Maths Compound Interest