A thief is noticed by a policeman from a distance of 200 meters. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km/h and 11 km/h respectively. What is the distance between them after 6 minutes? MCQ with Answer and Explanation

A thief is noticed by a policeman from a distance of 200 meters. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km/h and 11 km/h respectively. What is the distance between them after 6 minutes?
A. 180 meters
B. 190 meters
C. 150 meters
D. 100 meters
Answer: Option D
Solution (By JKSSB Mock Tests)
Relative speed = 11 - 10 = 1 km/h = 1 * (5/18) = 5/18 m/s. Distance covered in 6 minutes (360 seconds) = (5/18) * 360 = 100 meters. Remaining distance = 200 - 100 = 100 meters.

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Practice More Time Speed and Distance Questions

Question #1
A train tracking at 90 km/h clears a static warehouse tunnel in 20 seconds. If the train length is 150 meters, find the tunnel length.
A. 380 meters
B. 320 meters
C. 350 meters
D. 400 meters

Correct Answer: Option C


Explanation:
Speed of train = 90 * (5/18) = 25 m/s. Total distance covered in 20 seconds = 25 * 20 = 500 meters. Length of tunnel = 500 - 150 = 350 meters.

This question belongs to: Maths Time Speed and Distance
Question #2
A luxury car handles a tracking route sector of 240 km. It finishes the first half segment stretch at 40 km/h and the second half sector at 60 km/h. Find the mean average speed recorded across the full route.
A. 52 km/h
B. 46 km/h
C. 50 km/h
D. 48 km/h

Correct Answer: Option D


Explanation:
Average Speed across sectors = 2xy / (x + y) = (2 * 40 * 60) / (40 + 60) = 4800 / 100 = 48 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3
In a 200-meter sprint, X beats Y by 20 meters and Y beats Z by 10 meters. By how many meters does X beat Z in the same race?
A. 32 meters
B. 28 meters
C. 30 meters
D. 29 meters

Correct Answer: Option D


Explanation:
When X covers 200m, Y covers 180m. When Y covers 200m, Z covers 190m. Thus, when Y covers 180m, Z covers 190 * (180 / 200) = 171m. Therefore, when X covers 200m, Z covers 171m. X beats Z by 200 - 171 = 29 meters.

This question belongs to: Maths Time Speed and Distance