A town's population was 100,000 and is now 121,000. If the annual increase is 10%, in how many years did this increase occur? MCQ with Answer and Explanation

Question

A town's population was 100,000 and is now 121,000. If the annual increase is 10%, in how many years did this increase occur?

A. 4

B. 1

C. 3

D. 2

Answer: Option D

Solution (By JKSSB Mock Tests)

121000 = 100000 * (1.10)^t. 1.21 = (1.10)^t. Since 1.10^2 = 1.21, t = 2 years.

This question belongs to: Maths Percentage

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Question #1

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A number is decreased by 10% and then the new number is increased by 20%. If the resulting number is 540, find the original number.

A. 480

B. 450

C. 520

D. 500

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Correct Answer: Option D

Explanation:
0.9 × 1.2 = 1.08, 1.08x = 540 → x = 500.

This question belongs to: Maths Percentage

Question #2

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The marked price of an article is 50% above its cost price. The shopkeeper allows a discount of 20% and earns a profit of Rs. 60. Find the cost price.

A. Rs. 250

B. Rs. 200

C. Rs. 350

D. Rs. 300

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Correct Answer: Option D

Explanation:
CP=x, MP=1.5x, SP=1.5x×0.8=1.2x. Profit = 0.2x = 60 → x=300.

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Question #3

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One student scores 35% fails by 15, another 45% gets 25 more than pass. Pass marks:

A. 155

B. 150

C. 145

D. 160

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Correct Answer: Option A

Explanation:
0.35M+15=0.45M-25 → 0.1M=40 → M=400, pass=0.35×400+15=155.

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