A train 250 m long passes a man running at 5 kmph in the same direction in which the train is going, in 10 seconds. Find the speed of the train. MCQ with Answer and Explanation

A train 250 m long passes a man running at 5 kmph in the same direction in which the train is going, in 10 seconds. Find the speed of the train.
A. 90 kmph
B. 95 kmph
C. 80 kmph
D. 85 kmph
Answer: Option B
Solution (By JKSSB Mock Tests)
Relative speed = (250/10) m/s = 25 m/s = 90 kmph. Speed of train = relative speed + man's speed = 90 + 5 = 95 kmph. (Man running same direction, so train overtakes, relative speed = train speed - man speed). So train speed = 25 m/s + 5 kmph? 25 m/s = 90 kmph, man 5 kmph, so train 95 kmph. Yes.

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Practice More Percentage Questions

Question #1
Two alloys contain 70% and 40% copper respectively. In what ratio must they be mixed to obtain an alloy containing 50% copper?
A. 1:2
B. 3:2
C. 2:1
D. 1:1

Correct Answer: Option A


Explanation:
By alligation: (70-50):(50-40) = 20:10 = 2:1. The ratio of the alloys is inverse: 1:2.

This question belongs to: Maths Percentage
Question #2
The present value of a machine is 7,290. If it depreciates by 10% yearly, what was its value 3 years ago?
A. 12000
B. 10000
C. 9000
D. 11000

Correct Answer: Option B


Explanation:
V_past = 7290 / (0.90)^3 = 7290 / 0.729 = 10000.

This question belongs to: Maths Percentage
Question #3
A number is first increased by 20% and then decreased by 20%. What is the net percentage change in the number?
A. 10% decrease
B. 4% decrease
C. No change
D. 4% increase

Correct Answer: Option B


Explanation:
Let the number be 100. After 20% increase, it becomes 120. After 20% decrease, it becomes 120 * 0.8 = 96. Net change = 100 - 96 = 4% decrease.

This question belongs to: Maths Percentage