A wire of resistance 9 Ω is bent to form an equilateral triangle. The resistance across any two vertices is

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Total 9 Ω, each side 3 Ω. Across two vertices, one side is 3 Ω in parallel with series of two sides (3+3=6 Ω). Equivalent: (3×6)/(3+6) = 18/9 = 2 Ω. Triangle resistance network.

A wire of resistance 9 Ω is bent to form an equilateral triangle. The resistance across any two vertices is MCQ with Answer and Explanation

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