A wire of resistance 9 Ω is bent to form an equilateral triangle. The resistance across any two vertices is
A. 6 Ω
B. 2 Ω
C. 3 Ω
D. 9 Ω
Answer: Option B
Solution (By JKSSB Mock Tests)
Total 9 Ω, each side 3 Ω. Across two vertices, one side is 3 Ω in parallel with series of two sides (3+3=6 Ω). Equivalent: (3×6)/(3+6) = 18/9 = 2 Ω. Triangle resistance network.
According to Kepler's Third Law of Planetary Motion, the square of the time period of revolution of a planet around the Sun is directly proportional to:
A.The cube of the semi-major axis of its elliptical orbit
B.The square of the semi-major axis of its elliptical orbit
Explanation:
Kepler's Third Law (Law of Periods) states that the square of the time period (T^2) of any planet is proportional to the cube of the semi-major axis (r^3) of its orbit. Mathematically, T^2 is proportional to r^3. This law helps in calculating orbital periods or distances of planets and satellites.
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