Cost article Rs. 200, marked up 40%, then 20% discount. Selling price: MCQ with Answer and Explanation

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Cost article Rs. 200, marked up 40%, then 20% discount. Selling price:

A. 280

B. 224

C. 260

D. 240

Answer: Option B

Solution (By JKSSB Mock Tests)

Marked = 200×1.4 = 280, SP = 280×0.8 = 224.

This question belongs to: Maths Percentage

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Question #1

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In a mixture, the ratio of copper to zinc is 5:3. If 20% of the mixture is removed, what percentage of the remaining mixture is copper?

A. 70%

B. 60%

C. 50%

D. 62.5%

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Correct Answer: Option D

Explanation:
Removing part of the mixture does not change the ratio. Copper proportion = 5 / (5+3) = 5/8. Percentage = (5/8) * 100 = 62.5%.

This question belongs to: Maths Percentage

Question #2

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A number is increased by x% and then decreased by x%. The net decrease is 4%. Find x.

A. 18

B. 15

C. 10

D. 20

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Correct Answer: Option D

Explanation:
(1 + x/100)(1 - x/100) = 1 - (x²/10000) = 0.96 → x² = 400 → x = 20.

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Question #3

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The marked price of an article is 50% above its cost price. The shopkeeper allows a discount of 20% and earns a profit of Rs. 60. Find the cost price.

A. Rs. 200

B. Rs. 250

C. Rs. 350

D. Rs. 300

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Correct Answer: Option D

Explanation:
CP=x, MP=1.5x, SP=1.5x×0.8=1.2x. Profit = 0.2x = 60 → x=300.

This question belongs to: Maths Percentage

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