In a mixture, the ratio of copper to zinc is 5:3. If 20% of the mixture is removed, what percentage of the remaining mixture is copper? MCQ with Answer and Explanation

In a mixture, the ratio of copper to zinc is 5:3. If 20% of the mixture is removed, what percentage of the remaining mixture is copper?
A. 70%
B. 62.5%
C. 60%
D. 50%
Answer: Option B
Solution (By JKSSB Mock Tests)
Removing part of the mixture does not change the ratio. Copper proportion = 5 / (5+3) = 5/8. Percentage = (5/8) * 100 = 62.5%.

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Practice More Percentage Questions

Question #1
In a 40-litre mixture of milk and water, the ratio is 3:2. How many litres of water must be added to change the ratio to 1:2?
A. 28 L
B. 32 L
C. 24 L
D. 36 L

Correct Answer: Option B


Explanation:
Milk = 24, water = 16. For milk:water = 1:2, water = 48, add 32 L.

This question belongs to: Maths Percentage
Question #2
Allows 15% discount, still gains 19% profit. Markup % on CP:
A. 38%
B. 40%
C. 35%
D. 30%

Correct Answer: Option B


Explanation:
CP=100, SP=119, MP=119/0.85=140, markup 40%.

This question belongs to: Maths Percentage
Question #3
What is 30% of 30% of 200?
A. 18
B. 20
C. 30
D. 24

Correct Answer: Option A


Explanation:
0.3 × 0.3 × 200 = 18.

This question belongs to: Maths Percentage