In a mixture, the ratio of copper to zinc is 5:3. If 20% of the mixture is removed, what percentage of the remaining mixture is copper? MCQ with Answer and Explanation

In a mixture, the ratio of copper to zinc is 5:3. If 20% of the mixture is removed, what percentage of the remaining mixture is copper?
A. 50%
B. 62.5%
C. 70%
D. 60%
Answer: Option B
Solution (By JKSSB Mock Tests)
Removing part of the mixture does not change the ratio. Copper proportion = 5 / (5+3) = 5/8. Percentage = (5/8) * 100 = 62.5%.

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Practice More Percentage Questions

Question #1
Fresh grapes contain 68% water while dry grapes contain 20% water. How many kilograms of dry grapes can be obtained from 100 kg of fresh grapes?
A. 40 kg
B. 50 kg
C. 32 kg
D. 80 kg

Correct Answer: Option A


Explanation:
Quantity of pulp in fresh grapes = 100% - 68% = 32%. So, pulp = 32 kg. In dry grapes, pulp is 100% - 20% = 80%. Let dry grapes be D kg. 80% of D = 32 implies D = (32 / 0.8) = 40 kg.

This question belongs to: Maths Percentage
Question #2
Population 15000, first year +10%, second year -10%. Population after 2 years:
A. 15100
B. 15000
C. 14850
D. 14900

Correct Answer: Option C


Explanation:
15000×1.1×0.9 = 14850.

This question belongs to: Maths Percentage
Question #3
In a bag, 60% are red balls, 30% are blue balls, and the rest are green balls. If 5% of red, 10% of blue, and 20% of green balls are defective, what percent of the total balls are defective?
A. 7%
B. 8.5%
C. 7.5%
D. 8%

Correct Answer: Option D


Explanation:
Red=60, Blue=30, Green=10. Defective: Red 0.05×60=3, Blue 0.1×30=3, Green 0.2×10=2. Total defective=8%. So answer 8%.

This question belongs to: Maths Percentage