de Broglie wavelength λ = h/p. For electron, λ ∝:

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Team JKSSB Mock Tests · Accepted Answer

p = mv ⇒ λ = h/(mv) ⇒ λ ∝ 1/v for constant mass. Higher velocity ⇒ shorter wavelength. Memory tip: 'λ = h/mv; faster particle ⇒ smaller wavelength'. Quantum mechanics relation frequently tested in competitive modern physics sections.

de Broglie wavelength λ = h/p. For electron, λ ∝: MCQ with Answer and Explanation

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