During electrolysis of molten NaCl, the product at anode is: MCQ with Answer and Explanation

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During electrolysis of molten NaCl, the product at anode is:

A. Chlorine

B. Hydrogen

C. Oxygen

D. Sodium

Answer: Option A

Solution (By JKSSB Mock Tests)

At anode (oxidation): 2Cl⁻ → Cl₂ + 2e⁻ (chlorine gas). At cathode (reduction): Na⁺ + e⁻ → Na (liquid sodium). In aqueous NaCl, due to water, cathode produces H₂ and anode Cl₂ (or O₂ depending on concentration).

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Question #1

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Assertion (A): Radioactive decay is a nuclear process. Reason (R): It involves changes in the nucleus of an atom.

A. Both A and R are true and R is the correct explanation of A.

B. A is true but R is false.

C. A is false but R is true.

D. Both A and R are true but R is NOT the correct explanation of A.

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Correct Answer: Option A

Explanation:
Radioactive decay is a spontaneous process where an unstable atomic nucleus loses energy by emitting radiation. Since it involves the emission of particles (protons, neutrons, electrons) from the nucleus, it fundamentally alters the nucleus, making it a nuclear, not chemical, process.

This question belongs to: Science chemistry

Question #2

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Which of the following is an allotropic form of carbon used in lead pencils?

A. Diamond

B. Charcoal

C. Fullerene

D. Graphite

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Correct Answer: Option D

Explanation:
Graphite mixed with clay forms pencil 'lead'. Its layered structure marks paper. Diamond is used in cutting, fullerene in nanotechnology, charcoal in filters and fuel.

This question belongs to: Science chemistry

Question #3

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Assertion (A): Graphite is a good conductor of electricity. Reason (R): In graphite, each carbon atom uses three of its valence electrons to form covalent bonds, leaving one free delocalized electron.

A. Both A and R are true, and R is the correct explanation of A

B. A is true, but R is false

C. A is false, but R is true

D. Both A and R are true, but R is not the correct explanation of A

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Correct Answer: Option A

Explanation:
Graphite has a layered structure where each carbon is sp² hybridized, forming three sigma bonds with neighboring carbons, leaving one unhybridized p orbital electron delocalized over the entire layer. These mobile electrons allow electrical conduction parallel to layers. Diamond, with all four electrons in covalent bonds, is an insulator. Both the assertion and reason are correct, and the reason correctly explains the conductivity of graphite.

This question belongs to: Science chemistry

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