Find the mean proportional between 26 and 77. MCQ with Answer and Explanation

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Find the mean proportional between 26 and 77.

A. 44

B. 88

C. 47

D. 103

Answer: Option A

Solution (By JKSSB Mock Tests)

Mean proportional = √(26 × 77) = √(2002) = 44.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Ratio of present ages of A and B is 3:5. After 5 years, the ratio becomes 5:6. Present age of A is?

A. 36 years

B. 47 years

C. 84 years

D. 42 years

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Correct Answer: Option D

Explanation:
Let ages 3k and 5k. Then (3k + 5)/(5k + 5) = 5/6. Solving gives k ≈ 14, age of A = 3*14 = 42.

This question belongs to: Maths Ratio and Proportion

Question #2

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Two numbers are in the ratio 10:13 and their sum is 454. Find the numbers.

A. 204 and 226

B. 190 and 247

C. 380 and 494

D. 174 and 258

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Correct Answer: Option B

Explanation:
Numbers = 10k and 13k. 10k + 13k = 454 ⇒ k = 19. Thus, numbers are 190 and 247.

This question belongs to: Maths Ratio and Proportion

Question #3

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Two numbers are in ratio 4:12. Their difference is 122. What is their sum?

A. 244

B. 338

C. 104

D. 208

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Correct Answer: Option D

Explanation:
Numbers 4k, 12k. Difference |4-12|k = 122 ⇒ k = 15. Sum = (4+12)k ≈ 208.

This question belongs to: Maths Ratio and Proportion

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