If a body travels half the distance with speed v1 and remaining half with speed v2, average speed is MCQ with Answer and Explanation

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If a body travels half the distance with speed v1 and remaining half with speed v2, average speed is

A. (v1+v2)/2

B. 2v1v2/(v1+v2)

C. √(v1v2)

D. (v1+v2)/v1v2

Answer: Option B

Solution (By JKSSB Mock Tests)

Average speed = total distance / total time = d / ( (d/2)/v1 + (d/2)/v2 ) = 2v1v2/(v1+v2).

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Question #1

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A hydraulic press has area ratio 10:1. A force of 20 N on small piston can lift load of

A. 200 N

B. 20 N

C. 2 N

D. 2000 N

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Correct Answer: Option A

Explanation:
Pascal's law: F₁/A₁ = F₂/A₂ => F₂ = (A₂/A₁) F₁ = 10×20 = 200 N.

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Question #2

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A particle covers half of its total distance with speed v1 and the rest half distance with speed v2. Its average speed during the complete journey is:

A. 2(v1 * v2) / (v1 + v2)

B. (v1 * v2) / (v1 + v2)

C. (v1^2 + v2^2) / (v1 + v2)

D. (v1 + v2) / 2

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Correct Answer: Option A

Explanation:
When equal distances are covered with different speeds v1 and v2, the average speed is not the arithmetic mean, but the harmonic mean of the two speeds. Total distance = 2x. Total time = (x/v1) + (x/v2). Average speed = Total Distance / Total Time = 2x / [x(1/v1 + 1/v2)] = 2v1v2 / (v1 + v2).

This question belongs to: Science Physics