If the temperature of a gas is increased from 27°C to 327°C at constant pressure, the volume becomes how many times the original? MCQ with Answer and Explanation
If the temperature of a gas is increased from 27°C to 327°C at constant pressure, the volume becomes how many times the original?
A. 4 times
B. 2 times
C. 1.5 times
D. 3 times
Answer: Option B
Solution (By JKSSB Mock Tests)
Use Charles' law: V₁/T₁ = V₂/T₂. T in Kelvin: T₁ = 27+273 = 300 K, T₂ = 327+273 = 600 K. V₂/V₁ = T₂/T₁ = 600/300 = 2. Volume doubles. The ratio is 2:1. Note that 27 to 327 is a 300°C increase, but absolute temperature doubles.
Explanation:
Boyle's law: PV = constant (at fixed T and n). So P ∝ 1/V. If volume is doubled, pressure halves. Charles' law relates V and T; Graham's law relates diffusion rate to molar mass.
Explanation:
2H₂ + O₂ → 2H₂O is a combination reaction where two or more reactants combine to form a single product. A is decomposition. C is displacement. D is neutralization (also double displacement). Combination reactions are generally exothermic. Another example: C + O₂ → CO₂.
Explanation:
Dalton proposed that all atoms of a given element are identical in mass and properties. The discovery of isotopes (atoms of same element with different mass) contradicted this. Dalton's theory explained the three laws of chemical combination. Later models modified the theory. Subatomic particles and radioactivity also could not be explained by Dalton.
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