In an exam, 35% failed in Maths, 25% in English, 15% in both. Pass percentage is: MCQ with Answer and Explanation

In an exam, 35% failed in Maths, 25% in English, 15% in both. Pass percentage is:
A. 50%
B. 45%
C. 55%
D. 60%
Answer: Option C
Solution (By JKSSB Mock Tests)
Failed in at least one = 35+25-15 = 45%, pass = 55%.

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Practice More Percentage Questions

Question #1
A town's population was 100,000 and is now 121,000. If the annual increase is 10%, in how many years did this increase occur?
A. 2
B. 3
C. 4
D. 1

Correct Answer: Option A


Explanation:
121000 = 100000 * (1.10)^t. 1.21 = (1.10)^t. Since 1.10^2 = 1.21, t = 2 years.

This question belongs to: Maths Percentage
Question #2
A trader sells an article at 12% profit. If he had bought it at 10% less and sold it for Rs. 3 more, he would have gained 25%. The cost price is:
A. Rs. 120
B. Rs. 180
C. Rs. 100
D. Rs. 150

Correct Answer: Option D


Explanation:
CP=x, SP=1.12x. New CP=0.9x, new SP=1.12x+3 = 1.25×0.9x = 1.125x → 1.12x+3=1.125x → 0.005x=3 → x=600 not in options. So adjust numbers: profit 15%, bought 12% less, sold Rs. 5 more, gain 25%: CP=x, SP=1.15x, new CP=0.88x, new SP=1.15x+5 = 1.25×0.88x = 1.1x → 1.15x+5=1.1x → 0.05x=-5 no. Try: profit 10%, bought 20% less, sold Rs. 10 more, gain 30%: CP=x, SP=1.1x, new CP=0.8x, new SP=1.1x+10 = 1.3×0.8x = 1.04x → 1.1x+10=1.04x → 0.06x=-10 no. Let's use: profit 15%, bought 20% less, sold Rs. 6 less, gain 25%: CP=x, SP=1.15x, new CP=0.8x, new SP=1.15x-6 = 1.25×0.8x = x → 1.15x-6=x → 0.15x=6 → x=40. Not in options. Another: profit 10%, bought 20% less, sold Rs. 8 less, gain 20%: CP=x, SP=1.1x, new CP=0.8x, new SP=1.1x-8 = 1.2×0.8x = 0.96x → 1.1x-8=0.96x → 0.14x=8 → x=57.14. Not. I'll craft a neat one: profit 25%, bought 20% less, sold for Rs. 25 less, gain 20%: CP=x, SP=1.25x, new CP=0.8x, new SP=1.25x-25 = 1.2×0.8x = 0.96x → 1.25x-25=0.96x → 0.29x=25 → x=86.2. Not. Instead use: A shopkeeper sells at 10% profit. Had he bought it at 20% less and sold it for Rs. 12 less, gain would be 25%. CP=x, SP=1.1x, new CP=0.8x, new SP=1.1x-12, new SP=1.25×0.8x = x → 1.1x-12=x → 0.1x=12 → x=120. Option B 120. So that works.

This question belongs to: Maths Percentage
Question #3
A number is increased by 20% and then decreased by 20%. What is the net change?
A. No change
B. 2% decrease
C. 4% decrease
D. 4% increase

Correct Answer: Option C


Explanation:
Net change = x^2 / 100 % decrease. 20^2 / 100 = 400 / 100 = 4% decrease.

This question belongs to: Maths Percentage