Magnetic field around straight current-carrying wire is: MCQ with Answer and Explanation

Magnetic field around straight current-carrying wire is:
A. Parallel to wire
B. Radial
C. Uniform
D. Circular concentric
Answer: Option D
Solution (By JKSSB Mock Tests)
Biot-Savart law: field forms concentric circles around wire, direction by right-hand thumb rule. Magnitude B = μ₀I/(2πr), decreasing with distance. Memory tip: 'Right-hand rule: thumb = current, fingers = field circles'. Fundamental magnetism concept frequently tested in competitive exams.

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Practice More Physics Questions

Question #1
A body is projected vertically upwards with initial velocity u. The time taken to reach maximum height is:
A. 2u/g
B. u/g
C. g/u
D. u/(2g)

Correct Answer: Option B


Explanation:
At maximum height, final velocity v = 0. Using v = u - gt (taking upward positive), 0 = u - gt ⇒ t = u/g. This is time of ascent. Total time of flight would be 2u/g. The equation derives from Newton's first equation of motion under constant acceleration g downward. Memory aid: Time to peak = initial velocity / gravitational acceleration. This fundamental result appears in projectile motion problems. Competitive exams often combine this with energy conservation or symmetry concepts for advanced questions.

This question belongs to: Science Physics
Question #2
The coefficient of performance of a refrigerator is defined as:
A. Work input / Heat extracted
B. Heat extracted / Work input
C. Work input / Heat rejected
D. Heat rejected / Work input

Correct Answer: Option B


Explanation:
Coefficient of performance (COP) for refrigerator: COP = Q₂ / W, where Q₂ is heat extracted from cold reservoir, W is work input. By energy conservation, Q₁ = Q₂ + W (heat rejected to hot reservoir). COP > 1 typically. Option A is inverse; C and D relate to heat engine efficiency. Memory aid: 'Refrigerator COP = desired output (cooling) / work input'. This thermodynamics definition is frequently tested in competitive exams. Always distinguish refrigerator COP (cooling effect per work) from heat engine efficiency (work output per heat input).

This question belongs to: Science Physics
Question #3
The moment of inertia of a thin rod of mass M and length L about an axis through its centre and perpendicular to length is
A. ML²/12
B. ML²/3
C. ML²
D. ML²/2

Correct Answer: Option A


Explanation:
I_center = ML²/12. About end = ML²/3.

This question belongs to: Science Physics