Numerator of a fraction increased by 20%, denominator decreased by 10%, fraction becomes 2/3. Original fraction: MCQ with Answer and Explanation

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Numerator of a fraction increased by 20%, denominator decreased by 10%, fraction becomes 2/3. Original fraction:

A. 3/5

B. 1/2

C. 1/3

D. 2/5

Answer: Option B

Solution (By JKSSB Mock Tests)

(1.2a)/(0.9b) = 2/3 → (4/3)(a/b)=2/3 → a/b = 1/2.

This question belongs to: Maths Percentage

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Question #1

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Fresh grapes contain 68% water while dry grapes contain 20% water. How many kilograms of dry grapes can be obtained from 100 kg of fresh grapes?

A. 80 kg

B. 32 kg

C. 40 kg

D. 50 kg

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Correct Answer: Option C

Explanation:
Quantity of pulp in fresh grapes = 100% - 68% = 32%. So, pulp = 32 kg. In dry grapes, pulp is 100% - 20% = 80%. Let dry grapes be D kg. 80% of D = 32 implies D = (32 / 0.8) = 40 kg.

This question belongs to: Maths Percentage

Question #2

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If the numerator of a fraction is increased by 200% and the denominator is increased by 300%, the resultant fraction is 15/26. What was the original fraction?

A. 10/13

B. 11/14

C. 12/15

D. 8/11

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Correct Answer: Option A

Explanation:
Let original fraction be x/y. New numerator = x + 2x = 3x. New denominator = y + 3y = 4y. So, (3x / 4y) = 15/26. x/y = (15 * 4) / (26 * 3) = 60 / 78 = 10/13.

This question belongs to: Maths Percentage