Pendulum T measured 2.0±0.1 s. % error in g: MCQ with Answer and Explanation

Pendulum T measured 2.0±0.1 s. % error in g:
A. 20%
B. 10%
C. 2.5%
D. 5%
Answer: Option B
Solution (By JKSSB Mock Tests)
g = 4π²l/T² ⇒ %Δg = %Δl + 2×%ΔT. Assuming l precise: %Δg ≈ 2×(0.1/2.0×100%) = 2×5% = 10%. Memory tip: 'g ∝ 1/T² ⇒ %Δg = 2×%ΔT'. Error analysis frequently tested in competitive experimental physics sections.

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Practice More Physics Questions

Question #1
A convex lens forms a real image of an object. If the lower half of the lens is covered, the image will:
A. Be fainter but complete
B. Be half-formed
C. Disappear completely
D. Become virtual

Correct Answer: Option A


Explanation:
Covering part of a lens reduces the amount of light reaching the image, making it fainter, but the entire image is still formed because light from each object point can pass through the uncovered portion and converge to the corresponding image point. Image position, size, and nature remain unchanged. Memory aid: 'Partial lens coverage ⇒ reduced intensity, not partial image'. This conceptual question tests understanding of image formation principles, commonly featured in competitive exams to identify misconceptions about ray optics. Always recall that every point on lens contributes to entire image.

This question belongs to: Science Physics
Question #2
The kinetic energy of a body becomes four times its initial value. The new momentum will be:
A. Four times the initial
B. Twice the initial
C. Same as initial
D. Half the initial

Correct Answer: Option B


Explanation:
Kinetic energy KE = p²/(2m), where p is momentum. Thus p = √(2m·KE). If KE becomes 4 times, p_new = √(2m·4KE) = 2√(2m·KE) = 2p_initial. Hence momentum doubles. This relationship shows momentum scales with square root of kinetic energy for constant mass. Memory tip: p ∝ √KE when mass constant. This conceptual link between momentum and kinetic energy is frequently tested in competitive exams to assess depth of understanding beyond rote formula memorization. Always derive relationships when direct formulas aren't recalled.

This question belongs to: Science Physics
Question #3
The human ear can hear sound in frequency range
A. 20 Hz - 20 kHz
B. Above 200 kHz
C. 0-20 Hz
D. 20 kHz - 200 kHz

Correct Answer: Option A


Explanation:
Audible range: 20 Hz to 20,000 Hz (20 kHz). Below 20 Hz infrasound, above ultrasound. This range decreases with age. Dogs can hear higher frequencies (ultrasonic whistles).

This question belongs to: Science Physics