Pendulum T measured 2.0±0.1 s. % error in g: MCQ with Answer and Explanation

Pendulum T measured 2.0±0.1 s. % error in g:
A. 10%
B. 5%
C. 2.5%
D. 20%
Answer: Option A
Solution (By JKSSB Mock Tests)
g = 4π²l/T² ⇒ %Δg = %Δl + 2×%ΔT. Assuming l precise: %Δg ≈ 2×(0.1/2.0×100%) = 2×5% = 10%. Memory tip: 'g ∝ 1/T² ⇒ %Δg = 2×%ΔT'. Error analysis frequently tested in competitive experimental physics sections.

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