Polarization used in: MCQ with Answer and Explanation

Polarization used in:
A. Neither
B. Both
C. LCD displays
D. Glare-reducing sunglasses
Answer: Option B
Solution (By JKSSB Mock Tests)
Polarized sunglasses block reflected glare (horizontal polarization). LCDs use liquid crystals to rotate polarization for pixel control. Memory tip: 'Polarization: sunglasses (glare reduction), LCDs (display technology)'. Optics application frequently tested in competitive exams.

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Practice More Physics Questions

Question #1
The heating effect of electric current is described by:
A. Joule's law
B. Faraday's law
C. Lenz's law
D. Ohm's law

Correct Answer: Option A


Explanation:
Joule's law states that heat produced H = I²Rt, where I is current, R resistance, t time. This quantifies electrical energy converted to thermal energy in resistors. Ohm's law relates V, I, R; Faraday's and Lenz's laws concern electromagnetic induction. Memory aid: 'Joule heating ∝ I²R'. This definition-based question tests knowledge of fundamental laws in electricity, commonly examined in competitive exams. Applications include electric heaters, fuses, and incandescent bulbs. Always distinguish Joule's law (heating) from power formulas (P=VI=I²R=V²/R).

This question belongs to: Science Physics
Question #2
The value of universal gravitational constant G is
A. Both A and C
B. 6.67 × 10⁻¹¹ dyne cm²/g²
C. 9.8 m/s²
D. 6.67 × 10⁻¹¹ N m²/kg²

Correct Answer: Option A


Explanation:
G = 6.67 × 10⁻¹¹ N m²/kg² in SI, and 6.67 × 10⁻⁸ dyne cm²/g² in CGS. Both are correct. Important constant, measured by Cavendish. g is acceleration due to gravity, different.

This question belongs to: Science Physics
Question #3
A particle moves in a conservative force field where its potential energy U is given by U(x) = ax^2 - bx. The particle will be in stable equilibrium at position x equal to:
A. b / a
B. 2b / a
C. a / 2b
D. b / 2a

Correct Answer: Option D


Explanation:
Equilibrium occurs where the net force is zero, meaning dU/dx = 0. Given U(x) = ax^2 - bx, taking the derivative: dU/dx = 2ax - b = 0. Therefore, x = b / 2a. To confirm it's stable, the second derivative d^2U/dx^2 must be positive. d^2U/dx^2 = 2a. Assuming 'a' is positive, it represents a stable equilibrium point.

This question belongs to: Science Physics