Population of a town is 1,32,300 now. Increased 5% annually. Population 2 years ago: MCQ with Answer and Explanation

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Population of a town is 1,32,300 now. Increased 5% annually. Population 2 years ago:

A. 1,15,000

B. 1,18,000

C. 1,22,000

D. 1,20,000

Answer: Option D

Solution (By JKSSB Mock Tests)

Pop 2 years ago = 132300 / (1.05)² = 132300 / 1.1025 = 1,20,000.

This question belongs to: Maths Percentage

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Question #1

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A man sells two articles for Rs. 120 each. On one he gains 20%, and on the other he loses 20%. Find his overall profit or loss percent.

A. No profit no loss

B. 2% loss

C. 4% loss

D. 1% loss

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Correct Answer: Option C

Explanation:
CP1 = 120/1.2=100, CP2=120/0.8=150. Total CP=250, SP=240. Loss=10, %=(10/250)×100=4% loss.

This question belongs to: Maths Percentage

Question #2

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The present population of a town is 10,890. If it increases by 10% yearly, what was its population 2 years ago?

A. 9500

B. 10000

C. 9000

D. 8000

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Correct Answer: Option C

Explanation:
P_past = P_present / (1 + R/100)^2 = 10890 / (1.10)^2 = 10890 / 1.21 = 9000.

This question belongs to: Maths Percentage

Question #3

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A student multiplied a number by 7/4 instead of 4/7. What is the percentage error?

A. 206.25%

B. 150%

C. 200%

D. 100%

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Correct Answer: Option A

Explanation:
True = 4/7x. False = 7/4x. Error = (7/4 - 4/7)x = (33/28)x. % Error = ((33/28) / (4/7)) * 100 = (33/16) * 100 = 206.25%.

This question belongs to: Maths Percentage

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