The population of a town increases by 10% in the first year and decreases by 10% in the second year. If the present population is 19800, what was it 2 years ago? MCQ with Answer and Explanation

The population of a town increases by 10% in the first year and decreases by 10% in the second year. If the present population is 19800, what was it 2 years ago?
A. 18000
B. 20000
C. 21000
D. 19000
Answer: Option B
Solution (By JKSSB Mock Tests)
Present = original × 1.1 × 0.9 = 0.99 original. So original = 19800/0.99 = 20000.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Percentage Questions

Question #1
In an election, 20% of the votes were declared invalid. The winner got 70% of the valid votes and won by 1600 votes. Find the total number of votes polled.
A. 8000
B. 4000
C. 5000
D. 6000

Correct Answer: Option C


Explanation:
Winner got 70%, Loser 30% of valid votes. Difference = 40% of valid votes = 1600. Valid votes = 4000. Valid votes = 80% of total. Total = 4000 / 0.8 = 5000.

This question belongs to: Maths Percentage
Question #2
45 is what percentage of 90?
A. 40%
B. 50%
C. 55%
D. 45%

Correct Answer: Option B


Explanation:
(45 / 90) * 100 = 50%.

This question belongs to: Maths Percentage
Question #3
Spends 20% rent, 15% food, 25% education, 10% others, saves Rs. 18000. Salary:
A. 55000
B. 50000
C. 65000
D. 60000

Correct Answer: Option D


Explanation:
Total spend 70%, save 30% = 18000, salary = 18000/0.3 = 60000.

This question belongs to: Maths Percentage