The population of a town increases by 10% in the first year and decreases by 10% in the second year. If the present population is 19800, what was it 2 years ago? MCQ with Answer and Explanation

The population of a town increases by 10% in the first year and decreases by 10% in the second year. If the present population is 19800, what was it 2 years ago?
A. 18000
B. 19000
C. 20000
D. 21000
Answer: Option C
Solution (By JKSSB Mock Tests)
Present = original × 1.1 × 0.9 = 0.99 original. So original = 19800/0.99 = 20000.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Percentage Questions

Question #1
A's salary is 20% less than B's salary. By what percent is B's salary more than A's?
A. 25%
B. 20%
C. 27.5%
D. 22.5%

Correct Answer: Option A


Explanation:
Let B=100, A=80. B is (20/80)×100 = 25% more than A.

This question belongs to: Maths Percentage
Question #2
A man's income is 80% of his friend's income. The friend's expenditure is 60% of his income. If the man saves 30% of his income and the friend saves Rs. 4000, what is the man's income?
A. Rs. 8000
B. Rs. 12000
C. Rs. 15000
D. Rs. 10000

Correct Answer: Option A


Explanation:
Let friend's income = F. Friend saves 40% of F = 4000 → F = 10000. Man's income = 80% of F = 8000. Man saves 30% of 8000 = 2400. So answer Rs. 8000.

This question belongs to: Maths Percentage
Question #3
A sum of money at simple interest amounts to Rs. 920 in 3 years and to Rs. 1040 in 5 years. Find the principal.
A. Rs. 740
B. Rs. 720
C. Rs. 700
D. Rs. 760

Correct Answer: Option A


Explanation:
SI for 2 years = 1040-920 = 120, SI per year = 60. For 3 years, SI = 180, principal = 920-180 = 740.

This question belongs to: Maths Percentage