Potential energy of a body at a height h is 100 J. If height is doubled, the potential energy becomes
A. 100 J
B. 200 J
C. 400 J
D. 50 J
Answer: Option B
Solution (By JKSSB Mock Tests)
PE = mgh, so directly proportional to height h. If h becomes 2h, PE becomes 2 × 100 = 200 J, assuming g constant. For large heights, g varies, but basic assumption. Thus 200 J.
Explanation:
v = c/n = 3×10⁸/1.5 = 2×10⁸ m/s. Direct refractive index formula application. Memory tip: 'Higher n ⇒ slower light; v = c/n'. Basic optics calculation frequently tested in competitive exams to verify formula recall and unit handling.
Explanation:
Graphite, heavy water (D₂O), beryllium are moderators. Cadmium and boron are control rods (absorb neutrons). Uranium is fuel. Moderator slows neutrons.
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