Pressure at depth h in fluid: P = P₀ + ρgh. If depth doubles, pressure increase is: MCQ with Answer and Explanation

Pressure at depth h in fluid: P = P₀ + ρgh. If depth doubles, pressure increase is:
A. Double
B. Four times
C. Half
D. Same
Answer: Option A
Solution (By JKSSB Mock Tests)
Gauge pressure (excluding atmospheric) P_gauge = ρgh ∝ h. Doubling depth doubles gauge pressure. Total pressure P = P₀ + ρgh increases but not exactly double due to P₀ term. Question asks about pressure increase (ρgh part). Memory tip: 'Hydrostatic pressure ∝ depth'. Fundamental fluid statics concept frequently tested in competitive exams.

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Practice More Physics Questions

Question #1
An AC generator produces alternating current. To convert an AC generator into a DC generator, which crucial component must be replaced?
A. The split-ring commutator must be replaced with slip rings.
B. The armature coil must be made of aluminum.
C. The slip rings must be replaced with a split-ring commutator.
D. The magnetic poles must be swapped.

Correct Answer: Option C


Explanation:
An AC generator uses continuous 'slip rings' which allow the output polarity to reverse every half-rotation of the coil, generating alternating current. To produce direct current (DC), the slip rings must be replaced by a 'split-ring commutator'. This commutator reverses the connections to the external circuit at the exact moment the coil's current reverses, ensuring current flows in only one direction outside.

This question belongs to: Science Physics
Question #2
Assertion (A): The velocity of sound is greater in solids than in gases. Reason (R): Solids possess higher elasticity compared to gases.
A. A is true but R is false.
B. A is false but R is true.
C. Both A and R are true but R is NOT the correct explanation of A.
D. Both A and R are true and R is the correct explanation of A.

Correct Answer: Option D


Explanation:
The velocity of sound in a medium is determined by the formula v = √(E/ρ), where E is the modulus of elasticity and ρ is the density. Although solids are denser, their modulus of elasticity (bulk modulus) is tremendously higher than that of gases, overwhelmingly compensating for the density. Hence, sound travels fastest in solids.

This question belongs to: Science Physics
Question #3
Three resistors of 2Ω, 3Ω, and 6Ω are connected in parallel. The equivalent resistance is:
A. 0.5Ω
B. 11Ω
C.
D.

Correct Answer: Option D


Explanation:
For parallel combination: 1/R_eq = 1/R₁ + 1/R₂ + 1/R₃ = 1/2 + 1/3 + 1/6 = (3+2+1)/6 = 6/6 = 1. Thus R_eq = 1Ω. Note: Equivalent resistance in parallel is always less than the smallest individual resistance (here 2Ω). Memory tip: 'Parallel: reciprocal sum; result < min(R)'. This standard calculation tests parallel resistance formula application, frequently appearing in competitive exams. Always simplify fractions carefully; common denominator method avoids errors. Verify: 1Ω < 2Ω, consistent with parallel behavior.

This question belongs to: Science Physics