Projectile horizontal range maximum at angle: MCQ with Answer and Explanation

Projectile horizontal range maximum at angle:
A. 60°
B. 90°
C. 30°
D. 45°
Answer: Option D
Solution (By JKSSB Mock Tests)
Range R = u²sin(2θ)/g. sin(2θ) maximum (=1) when 2θ=90° ⇒ θ=45°. Standard result for level ground projection. Memory aid: 'Max range at 45°; max height at 90°'. Projectile motion fact frequently tested in competitive exams.

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