Projectile horizontal range maximum at angle: MCQ with Answer and Explanation

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Projectile horizontal range maximum at angle:

A. 60°

B. 30°

C. 90°

D. 45°

Answer: Option D

Solution (By JKSSB Mock Tests)

Range R = u²sin(2θ)/g. sin(2θ) maximum (=1) when 2θ=90° ⇒ θ=45°. Standard result for level ground projection. Memory aid: 'Max range at 45°; max height at 90°'. Projectile motion fact frequently tested in competitive exams.

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Question #1

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A satellite moves in a circular orbit around the Earth at a constant speed. The work done by the gravitational force on the satellite is:

A. Maximum

B. Positive

C. Negative

D. Zero

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Correct Answer: Option D

Explanation:
Work is defined as W = F.d.cos(θ). For a satellite in a circular orbit, the gravitational force acts as the centripetal force, directing entirely towards the center of the Earth. The displacement of the satellite at any instant is tangential. Since the angle between force and displacement is exactly 90°, cos(90°) = 0, meaning zero work is done.

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Question #2

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A geostationary satellite orbits the Earth from:

A. South to North

B. West to East

C. East to West

D. North to South

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Correct Answer: Option B

Explanation:
A geostationary satellite must appear stationary to an observer on the Earth's surface. To achieve this, it must orbit in the exact equatorial plane and strictly follow the Earth's rotation. Since the Earth rotates on its axis from West to East, the geostationary satellite must also orbit from West to East.

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