Ratio of present ages of A and B is 3:8. After 10 years, the ratio becomes 4:10. Present age of A is? MCQ with Answer and Explanation

Question

Share Report Error

Ratio of present ages of A and B is 3:8. After 10 years, the ratio becomes 4:10. Present age of A is?

A. 44 years

B. 56 years

C. 51 years

D. 102 years

Answer: Option C

Solution (By JKSSB Mock Tests)

Let ages 3k and 8k. Then (3k + 10)/(8k + 10) = 4/10. Solving gives k ≈ 17, age of A = 3*17 = 51.

This question belongs to: Maths Ratio and Proportion

Request complete Subject PDF

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Ratio and Proportion Questions

Question #1

Share Report

Milk and water are in ratio 5:2 in a 305 L mixture. Quantity of milk?

A. 434 L

B. 88 L

C. 265 L

D. 217 L

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option D

Explanation:
Total parts = 7. Milk = [5 / (5+2)] × 305 = 217 L.

This question belongs to: Maths Ratio and Proportion

Question #2

Share Report

Find the mean proportional between 34 and 17.

A. 48

B. 27

C. 24

D. 51

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option C

Explanation:
Mean proportional = √(34 × 17) = √(578) = 24.

This question belongs to: Maths Ratio and Proportion

Question #3

Share Report

Ratio of present ages of A and B is 3:5. After 6 years, the ratio becomes 4:7. Present age of A is?

A. 63 years

B. 58 years

C. 126 years

D. 68 years

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option A

Explanation:
Let ages 3k and 5k. Then (3k + 6)/(5k + 6) = 4/7. Solving gives k ≈ 21, age of A = 3*21 = 63.

This question belongs to: Maths Ratio and Proportion

Explore All Ratio and Proportion MCQs