Ratio of present ages of A and B is 3:8. After 10 years, the ratio becomes 4:10. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 3:8. After 10 years, the ratio becomes 4:10. Present age of A is?

A. 102 years

B. 56 years

C. 44 years

D. 51 years

Answer: Option D

Solution (By JKSSB Mock Tests)

Let ages 3k and 8k. Then (3k + 10)/(8k + 10) = 4/10. Solving gives k ≈ 17, age of A = 3*17 = 51.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Milk and water are in ratio 3:5 in a 587 L mixture. Quantity of milk?

A. 220 L

B. 367 L

C. 440 L

D. 248 L

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Correct Answer: Option A

Explanation:
Total parts = 8. Milk = [3 / (3+5)] × 587 = 220 L.

This question belongs to: Maths Ratio and Proportion

Question #2

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Two numbers are in the ratio 14:9 and their sum is 497. Find the numbers.

A. 588 and 378

B. 307 and 170

C. 286 and 198

D. 294 and 189

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Correct Answer: Option D

Explanation:
Numbers = 14k and 9k. 14k + 9k = 497 ⇒ k = 21. Thus, numbers are 294 and 189.

This question belongs to: Maths Ratio and Proportion

Question #3

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If a:b = 4:6 and b:c = 6:9, then a:b:c = ?

A. 3:6:10

B. 8:12:18

C. 4:7:9

D. 4:6:9

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Correct Answer: Option D

Explanation:
Combine ratios: a:b = 4:6, b:c = 6:9 ⇒ a:b:c = 4:6:9.

This question belongs to: Maths Ratio and Proportion

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