Ratio of present ages of A and B is 4:8. After 8 years, the ratio becomes 6:10. Present age of A is? MCQ with Answer and Explanation

Ratio of present ages of A and B is 4:8. After 8 years, the ratio becomes 6:10. Present age of A is?
A. 37 years
B. 44 years
C. 49 years
D. 88 years
Answer: Option B
Solution (By JKSSB Mock Tests)
Let ages 4k and 8k. Then (4k + 8)/(8k + 8) = 6/10. Solving gives k ≈ 11, age of A = 4*11 = 44.

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Practice More Ratio and Proportion Questions

Question #1
Ratio of present ages of A and B is 7:8. After 12 years, the ratio becomes 8:9. Present age of A is?
A. 77 years
B. 82 years
C. 70 years
D. 154 years

Correct Answer: Option A


Explanation:
Let ages 7k and 8k. Then (7k + 12)/(8k + 12) = 8/9. Solving gives k ≈ 11, age of A = 7*11 = 77.

This question belongs to: Maths Ratio and Proportion
Question #2
Two numbers are in ratio 4:12. Their difference is 122. What is their sum?
A. 208
B. 104
C. 338
D. 244

Correct Answer: Option A


Explanation:
Numbers 4k, 12k. Difference |4-12|k = 122 ⇒ k = 15. Sum = (4+12)k ≈ 208.

This question belongs to: Maths Ratio and Proportion
Question #3
Two numbers are in the ratio 12:9 and their sum is 368. Find the numbers.
A. 408 and 306
B. 187 and 162
C. 204 and 153
D. 219 and 124

Correct Answer: Option C


Explanation:
Numbers = 12k and 9k. 12k + 9k = 368 ⇒ k = 17. Thus, numbers are 204 and 153.

This question belongs to: Maths Ratio and Proportion