Two numbers are in ratio 4:12. Their difference is 122. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 4:12. Their difference is 122. What is their sum?

A. 244

B. 208

C. 104

D. 338

Answer: Option B

Solution (By JKSSB Mock Tests)

Numbers 4k, 12k. Difference |4-12|k = 122 ⇒ k = 15. Sum = (4+12)k ≈ 208.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Ratio of present ages of A and B is 3:6. After 11 years, the ratio becomes 5:9. Present age of A is?

A. 114 years

B. 62 years

C. 49 years

D. 57 years

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Correct Answer: Option D

Explanation:
Let ages 3k and 6k. Then (3k + 11)/(6k + 11) = 5/9. Solving gives k ≈ 19, age of A = 3*19 = 57.

This question belongs to: Maths Ratio and Proportion

Question #2

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If a:b = 5:9 and b:c = 9:11, then a:b:c = ?

A. 5:9:11

B. 4:9:12

C. 5:10:11

D. 10:18:22

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Correct Answer: Option A

Explanation:
Combine ratios: a:b = 5:9, b:c = 9:11 ⇒ a:b:c = 5:9:11.

This question belongs to: Maths Ratio and Proportion

Question #3

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If a:b = 7:4 and b:c = 4:4, then a:b:c = ?

A. 7:5:4

B. 14:8:8

C. 6:4:5

D. 7:4:4

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Correct Answer: Option D

Explanation:
Combine ratios: a:b = 7:4, b:c = 4:4 ⇒ a:b:c = 7:4:4.

This question belongs to: Maths Ratio and Proportion

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